Ratio to Interval Scale
Number As Product As Power As Log
100,000. 10X10X10X10X10 105 5
10,000. 10X10X10X10 104 4
1,000. 10X10X10 103 3
100. 10X10 102 2
10. 10 101 1
1. 1 100 0
0.1 1/10 10-1 -1
0.01 1/(10X10) 10-2 -2
0.001 1/(10X10X10) 10-3 -3
0.0001 1/(10X10X10X10) 10-4 -4
0.00001 1/(10X10X10X10X10) 10-5 -5
Now here's the good part. If we need to know the product of two large numbers, say 1000 and 100,000, we don't have to multiply. In our new counting system, the product of these two numbers is represented by the sum of their log values. The log of 1000 is 3, the log of 100,000 is 5, and so the log of 1000 times 100,000 is 3+5 or 8. The same is true for division. Express the ratio 10/10,000 as a log value. The log of 10 is 1, the log of 1/10,000 is -4, adding the log values yields -3 which is the log of 10/10,000.
OK - OK all this is very simple you say - but does this mean that every number we encounter will be a factor of 10? The answer is of course no - but this poses no real problem. We know that a factor of 10 corresponds to 1 log unit. Any other factor less than 10 (i.e. 2, 3, 4, etc.) must therefore correspond to some fraction of a log unit. For our purposes we need only remember one of these values. We will remember that a factor of 2 corresponds to one-third of a log unit, that is log(2) = 0.3. What is the log of 20,000? Well, 20,000 is 2X10,000. The log of 2 is 0.3 and the log of 10,000 is 4. Therefore the log of 20,000 is 0.3+4 or 4.3.
Laws of Logarithms
i. log(xy) = log(x) + log(y)
ii. log(x/y) = log(x) - log(y)
iii. log(xn) = nlog(x)
iv. log(0) is undefined